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Solve for x and y in the logarithmic system of equations:

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log{3}(x-2y)+ log{3}(3x+2y) = 3.
asked Mar 12, 2014 in ALGEBRA 2 by johnkelly Apprentice

1 Answer

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log{3}(x-2y)+ log{3}(3x+2y) = 3.

Using the product rule loga x + loga y =loga (xy)

log{3}(x-2y)(3x+2y) = 3.

Using basic definition of the logathim

loga x = N means that aN = x.

(x-2y)(3x+2y) =3^3

(x-2y)(3x+2y) =27

answered Apr 22, 2014 by bradely Mentor

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