What is the radius of the circle whose equation is x^2+ y^2 = 8?

Question

how would you go about solving this

Answer 1

The equation is x^2+y^2 = 8.

Rewrite the equation as x^2 + y^2 = (√8)^2.

Compare the above equation with standard form of a circle (x - h)^2 + (y - k)^2 = r^2, where, center (h, k) = (0, 0) and radius = r.

Center (h, k) = (0, 0) and radius (r) = √8.

Therefore, radius of the circle is √8.