Welcome :: Homework Help and Answers :: Mathskey.com

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,220)
GEOMETRY (864)
ALGEBRA 2 (2,751)
TRIGONOMETRY (1,187)
PRECALCULUS (1,903)
CALCULUS (2,802)
STATISTICS (129)
PHYSICS (659)
CHEMISTRY (137)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration limits substitution-method calculus

13,459 questions

17,854 answers

1,446 comments

807,969 users

If 10sin^(4)A + 15cos^(4)A = 6

0 votes

then find the value of 27cosec^(6)A + 8sec^(6)A?

trigonometric-identities

asked Jun 24, 2014 in TRIGONOMETRY by anonymous

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

Therefore adjacent side = sqrt(2).

Therefore

Therefore 27cosec⁶A + 8sec⁶A = 250.

answered Jun 24, 2014 by joly Scholar

Please log in or register to add a comment.

Related questions

show that tan(Π/4+A) and tan(Π/4-A)=1

asked Jan 7, 2017 in TRIGONOMETRY by anonymous

trigonometric-identities

show that tan(A+Π/4)=cosA+sinB/cosA-sinA.

asked Jan 6, 2017 in TRIGONOMETRY by anonymous

trigonometric-identities

show that tan(A+Π/4)=cosA+sinA/cosA-sinA

asked Jan 6, 2017 in TRIGONOMETRY by anonymous

trigonometric-identities

If θ is in quadrant II and cos θ = − 2/3

asked Dec 22, 2017 in TRIGONOMETRY by anonymous

double-angle
trigonometric-identities

If sinx + sin^2x=1,

asked Jun 11, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

if sinθ = 1/2(x+1/x), show that sin 3θ + 1/2 (x^3 + 1/x^3) = 0

asked Nov 30, 2013 in TRIGONOMETRY by skylar Apprentice

trigonometric-identities

if cosA+sinA=2^1/2*cosA, then show that cosA-sinA=2^1/2*sinA.

asked Oct 24, 2013 in TRIGONOMETRY by andrew Scholar

trigonometric-identities

solve sinxcos(π/6) + sin(π/6)cosx= 1/√2

asked Nov 20, 2013 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

How do you solve (sec^2)+(tan^2)+6 with trig identities?

asked Feb 22, 2013 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

Tan (x+π/4)= (cosx + sinx)/(cosx-sinx) How do I prove this?

asked Nov 13, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

Can anyone prove that 5sin^2 A+ 3cos^2 A= 2sin^2 A+3?

asked Apr 13, 2016 in TRIGONOMETRY by anonymous

trigonometric-identities
homework-help

Help with simplifying a trigonometric expression?

asked Mar 10, 2015 in TRIGONOMETRY by anonymous

trigonometric-functions
trigonometric-identities

use the trigonometric substitution to write the algebraic equation as a trigonometric equation of

asked Jan 19, 2015 in TRIGONOMETRY by anonymous

trigonometric-identities

How do I find a formula that expresses

asked Dec 13, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

Prove tan(60+A)tan(60-A)=2cos2A+1/2cos2A-1

asked Oct 28, 2014 in TRIGONOMETRY by anonymous

trigonometric-identities

use the trigonometric substitution to write the algebraic expression as a trigonometric function of θ, where 0<θ<∏/2

asked Mar 5, 2014 in TRIGONOMETRY by skylar Apprentice

trigonometric-identities
trigonometric-functions

cosecA+cotA=cot A/2

asked Feb 28, 2014 in TRIGONOMETRY by payton Apprentice

trigonometric-identities
trigonometric-equation

Prove that (1 - sin 2A)/(1 + sin 2A) = (1 - tan A)/(1 + tan A)

asked Nov 30, 2013 in TRIGONOMETRY by angel12 Scholar

trigonometric-identities

Help with a Trigonometry Problem?

asked Jul 10, 2013 in TRIGONOMETRY by anonymous Apprentice

trigonometric-identities

proving a trig identity

asked Feb 14, 2013 in TRIGONOMETRY by payton Apprentice

trigonometric-identities

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...