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X^3+2x^2-15x-36 = 0 factor theorem???

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Show me please!!?

factor-theorem

asked Jul 14, 2014 in ALGEBRA 1 by anonymous

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1 Answer

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The equation is x³ + 2x² - 15x - 36 = 0.

By factor by grouping.

x³ + 2x² - 15x - 36 = 0

x³ - 4x²+ 6x² - 15x - 36 = 0

x²(x - 4) + [6x² - 24x + 9x - 36] = 0

x²(x - 4) + [6x(x - 4) + 9(x - 4)] = 0

x²(x - 4) + [(x - 4)(6x + 9)] = 0

Factor : (x - 4)(x² + 6x + 9) = 0

(x - 4)(x + 3)² = 0.

answered Jul 14, 2014 by lilly Expert

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