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HOW TO CALCULATE THE FOLLOWING?

0 votes
A tensile load of 10 kN is applied to a bar with a square cross sectional area. The lengths of the sides are 194 mm each and the bar is TWO metres long. The total change in length is 0,231 mm. Calculate, The stress, The strain, Young's Modulus of Elasticity
asked Jul 14, 2014 in PHYSICS by anonymous

2 Answers

0 votes

Given,

Tensile load ,P = 10 kN =10000 N

Side length of the square bar,= 194 mm =0.194 m

Length of the bar, l =2 m

Change in length of the bar, Δl  = 0.231 mm =0.000231 m

-------------------------------

Calculate area of the square bar.

A = a2

    = 0.1942

   = 0.037636 m2

Calculate the young modulus of the bar:

Δl = Pl / AE

=Pl / Δl A

E = (10000)(2) / (0.000231)(0.037636)

   = 23×10Pa

 

Therfore, the young modulus of the bar is 23×10Pa

 

     

answered Jul 15, 2014 by bradely Mentor
0 votes

Calculate stress in the bar.

σ= P / A

  =  100000.037636

  =26.57 ×10Pa

 

Therfore, the stress in the bar is 26.57×10Pa

-------------------------------

Calculate the strain (ε ) in the bar.

ε σE

  =  26.57 ×10 /  23×108

   =   1.155 ×10-4 m/m

 

Therfore, the strain (ε ) in the bar is 1.155 ×10-4  m/m

 
answered Jul 15, 2014 by bradely Mentor

strain (ε) = change in length) / (original length).

ε = Δl / l

  = 0.000231 m/2 m (Remeber Units must be same)

  =1.155 ×10-4

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