Range of

Question

y=√((1-√(1-x^2))/2)? thanks a lot :)?

Answer 1

The range and domain of square root function ( y = √x) is the set of all negative real numbers.

The equation is y=√((1-√(1-x²))/2).

In the equation, x represents the domain and y represent the range.

The domain of equation is (1 - x²) ≥ 0 ⇒ 1 ≥ x² ⇒ - 1 ≤ x ≤ 1.

Find y - value at maximum value of x = 1.

y=√((1-√(1-1²))/2)

y=√((1-0)/2)

y=√(0.5)

y=0.7.

Find y - value at minimum value of x = -1.

y=√((1-√(1-(-1)²))/2)

y=√((1-0)/2)

y=√(0.5)

y=0.7

The maximum y value is 0.7.

The range of the original function is [0, 0.7].