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Find the indefinite integral of

0 votes

1/(6x)^1/2?

1/(6x)^1/2

Help is appreciated.

integration

asked Jul 21, 2014 in CALCULUS by anonymous

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1 Answer

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Therefore integral of 1 / (6x)^1/2 = 1/3 [√(6x)] + C or √(2/3) √(x) + C.

answered Jul 21, 2014 by joly Scholar

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