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Find the sum of the first 6 terms of a geometric sequence

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 if the first term is 5 and the common ratio is -4..

asked Jul 25, 2014 in ALGEBRA 2 by anonymous

1 Answer

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Given : Number of terms, n = 6, first term, a1 = 5 and common ratio, r = - 4.Sn =

The sum of the first n terms of the geometric sequence : Sn = a1[(1 - rn)/(1 - r)], r ≠ 1.

Substitute the corresponding values.

S6 = 5[(1 - (- 4)6)/(1 - (- 4))]

S6 = 5[(1 - 46)/(1 + 4)]

S6 = 5[(1 - 4096)/5]

S6 = 5[(- 4095)/5]

S6 = - 4095.

Therefore, the sum of the first 6 terms of the geometric sequence is - 4095.

answered Jul 25, 2014 by lilly Expert

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