Given that 2p-m=6 and 2p+4m=1 find the value of (4p+3m)

Answer 1

Subtract the equations from one another.

2p - m = 6

2p + 4m = 1

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-5m = 5

m = -1

 

Substitute m = -1 in 2p - m = 6

2p + 1 = 6

p = 5/2.

 

Substitute p = 5/2/ m = -1 in 4p + 3m

= 4* 5/2 + 3(-1)

=10 - 7

= 3

 

THe solution is 4p + 3m = 3

Comments

4p + 3m = 4*(5/2) + 3(- 1)

= 10 - 3

= 7.

Therefore, the value of (4p + 3m) is 7.