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Derive the identity

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sin2x = 2sinx cosx
asked Aug 26, 2014 in TRIGONOMETRY by anonymous

1 Answer

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The function is sin2x = 2sinx cosx

sin2x = sin (x + x)

Recall the trigonometry compound angles formula:  sin (A + B) = sinA cosB + cosA sinB

sin (x + x) = sinx cosx + cosx sinx

 sin (x + x) = sinx cosx + sinx cosx

 sin (x + x) = 2sinx cosx

Therefore  sin2x = 2sinx cosx

answered Aug 26, 2014 by anonymous
edited Aug 26, 2014 by bradely

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