I need help figuring out how to factor out this problem

Question

(3x+2)^2+8(3x+2)+12 Thanks in advance for the help!? 

Update : The answer in the back of the book is supposed to be: (3x+4)(3x+8)

 

Answer 1

Given (3x+2)² + 8(3x+2) + 12 

Let (3x+2) = y

So the equetion becomes y² + 8y + 12 

y² + 8y + 12 

y² + 6y + 2y + 12 

y (y+6) + 2(y+6) 

(y+6)(y+2) 

Now put y=3x +2

(3x+2+6)(3x+2+2) 

(3x+8)(3x+4)