Physics Help?

Question

.​James Bond is on a bridge. He drops vertically from rest into a powerboat that is about to pass under the bridge. The boat is moving toward the bridge with a constant speed of 15.5 m/s, and Mr. Bond is initially 3.50 m above the boat. ​(10 points) 

a. How long is James Bond in the air? 

b.​How far away horizontally must the boat be when Mr. Bond drops so that he will successfully land in the boat?

 

Answer 1

(a)

Here in this case the body ( Mr bond ) is free falling form a certain height so intial velocity (u =0)

Time taken for a freely falling body to reach ground ( t ) = 

Height (h) = 3.5 m  Value of g = 9.8 m/s²

So time taken to reach boat ( or ) time ramains in air ( t ) = 

t = 0.845 sec

So Mr bond ramains in air for time  t = 0.845 sec

Answer 2

(b)

The speed of the boat is (v) =15.5 m/s

Time taken for Mr bond to reach boat = t = 0.845 sec

For successfully land in the boat , the distance of the boat from that point where Mr bond drop into boat (d) 

Distance d = velocity × time 

d = 15.5× 0.845

d = 13.0975 m

The boat is 13.0975 m  far away from  Mr. Bond for successfully land in the boat