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Find the exact value of

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Find the exact value of cosine of theta over 2 given sine of theta = 5 over 13 and theta is between 90 degrees and 180 degrees..
A. image
B. image
C. image
D. image
Find the exact value of cos 2 theta given cosine of theta = negative 12 over 13 and theta is between 180 degrees and 270 degrees.
A. image
B. image
C. image
D. image

 

asked Oct 2, 2014 in TRIGONOMETRY by tonymate Pupil

2 Answers

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Best answer

1) sin(θ) = 5/13

θ is in second quadrant.

sin(θ) = [ Opposite side ]/[ Hypotenuse ]

From the pythageron therom ,

Adjacent side = √[(hypotenuse)2 - (opposite side)2 ]

= √[(13)2 - (5)2 ]

= √[169 - 25 ]

= √144

Adjacent side = 12

cos(θ) = [ adjacent side ]/[hypotenuse ]

cos(θ) = - 12/13

Apply the half angle identity cos(θ/2) =  √[(1 + cos(θ))/2]

cos(θ/2) = √[ 1 + (-12/13)]/2

= √[13-12]/2(13)

= √1/2(13)

=  1/√26

=  26/[26(√26)]

= √26/26

Option D is correct choice.

answered Oct 2, 2014 by david Expert
selected Oct 2, 2014 by tonymate
0 votes

2)cos(θ) = -12/13

θ is in third quadrant.

Apply the double angle identity cos(2θ) = 2cos2θ - 1 

= 2 (-12/13)2 - 1 

= 2(144/169) - 1

= (288/169) - 1

= ( 288 - 169)/169

= 119/169

Option B is correct choice.

answered Oct 2, 2014 by david Expert

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