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Need to check my horitontal asymptotes question

0 votes

Please show me how to do it also. Also when I am doing this question, I only look at the biggest exponent when applying my rule right? I don't care about the number before the x, just the highest exponent. Well what if the top has x^2 and bot have no x? or what if x^3/x?

asked Oct 6, 2014 in PRECALCULUS by Baruchqa Pupil

2 Answers

+1 vote

(8).

The function is f(x) = 1 / (x2 - 8x + 15).

In the above function, numerator function [N(x) = 1] and denominator function [D(x) = x2 - 8x + 15] have no common factors.

The graph of f(x) function has one or no horizontal asymptote determined by comparing the degrees of numerator function and denominator function.

Degree of numerator function( = 0) < Degree of denominator function( = 2).

Therefore, horizontal asymptote is y = 0( the x-axis).

The horizontal asymptote y = 0.

answered Oct 6, 2014 by casacop Expert
+1 vote

(9).

The function is f(x) = (3x2 - 100) / (x2 + 1000).

In the above function, numerator function [N(x) = 3x2 - 100] and denominator function [D(x) = x2 + 1000] have no common factors.

The graph of f(x) function has one or no horizontal asymptote determined by comparing the degrees of numerator function and denominator function.

Degree of numerator function = 2 = Degree of denominator function.

Therefore, horizontal asymptote is y = an/bn = leading coefficient of numerator function / leading coefficient of denominator function = 3/1 = 3.

The horizontal asymptote y = 3.

 

answered Oct 6, 2014 by casacop Expert

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