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Find the vertex of the parabola

y = f(x)= 23 (x-14)^2


x coordinate = y coordinate =  
Graph this function and estimate the x intercepts to the nearest tenth. Give your answers in order. 
x intercept one = x intercept two = 

 

 

asked Oct 8, 2014 in PRECALCULUS by Baruchqa Pupil

1 Answer

+1 vote

The parabola in vertex form  y = 23(x - 14)2

Write the equation in the form y = ax2  + bx + c.

y = 23(x2  + 196 - 28x)

y = 23x2 + 4508 - 644x

y = 23x2- 644x + 4508

Compare it to parabola equation y = ax2  + bx + c.

a = 23, b = - 644, c = 4508

Axis of symmetry x = -b/2a

x = -(-644)/2(23)

x = 644/46

x = 14

Substitute x = 14 in y = 23x2 + 4508 - 644x

y = 23(14)2 - 644(14) + 4508

y = 0

Vertex of parabola (14, 0)

x coordinate of vertex is 14

y coordinate of vertex is 0.

To find x intercept substitute y = 0 in  y = 23(x - 14)2

23(x - 14)2 = 0

(x - 14)2 = 0

x - 14 = 0

x = 14

In this case only one xintercept .

x intercept is 14

Graph

 

 

answered Oct 8, 2014 by david Expert

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