Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,748 users

stuck on these

0 votes

Find the vertex of the parabola

y = f(x)= 23 (x-14)^2


x coordinate = y coordinate =  
Graph this function and estimate the x intercepts to the nearest tenth. Give your answers in order. 
x intercept one = x intercept two = 

 

 

asked Oct 8, 2014 in PRECALCULUS by Baruchqa Pupil

1 Answer

+1 vote

The parabola in vertex form  y = 23(x - 14)2

Write the equation in the form y = ax2  + bx + c.

y = 23(x2  + 196 - 28x)

y = 23x2 + 4508 - 644x

y = 23x2- 644x + 4508

Compare it to parabola equation y = ax2  + bx + c.

a = 23, b = - 644, c = 4508

Axis of symmetry x = -b/2a

x = -(-644)/2(23)

x = 644/46

x = 14

Substitute x = 14 in y = 23x2 + 4508 - 644x

y = 23(14)2 - 644(14) + 4508

y = 0

Vertex of parabola (14, 0)

x coordinate of vertex is 14

y coordinate of vertex is 0.

To find x intercept substitute y = 0 in  y = 23(x - 14)2

23(x - 14)2 = 0

(x - 14)2 = 0

x - 14 = 0

x = 14

In this case only one xintercept .

x intercept is 14

Graph

 

 

answered Oct 8, 2014 by david Expert

Related questions

asked Sep 18, 2014 in ALGEBRA 1 by anonymous
asked Apr 24, 2016 in PRECALCULUS by anonymous
asked Apr 9, 2016 in PRECALCULUS by anonymous
asked Feb 27, 2016 in PRECALCULUS by anonymous
asked Oct 10, 2019 in ALGEBRA 1 by anonymous
...