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Find the vertex of the parabola

y = f(x)= x^2 + 8 x - 9


x coordinate = y coordinate =  
Graph this function and estimate the x intercepts to the nearest tenth. Give your answers in order. 
x intercept one = x intercept two = 

 
asked Oct 8, 2014 in PRECALCULUS by Baruchqa Pupil

1 Answer

+1 vote

The parabola equation y = x2  + 8x - 9

Compare it to parabola equation y = ax2  + bx + c.

a = 1, b = 8, c = - 9

Axis of symmetry x = - b/2a

x = - 8/2(1)

x = - 4

Substitute x = - 4 in y = x2  + 8x - 9

y = (- 4)2  + 8(- 4) - 9

y =  - 25

Vertex of parabola is (x, y) = (- 4, - 25).

To find x intercepts substitute y = 0 in y = x2  + 8x - 9.

x2  + 8x - 9 = 0

Solve the equation for x.

x2  + 9x - x - 9 = 0

x ( x + 9) - 1(x + 9) = 0

(x + 9)(x - 1) = 0

x + 9 = 0 and x + 1 = 0

x intercepts are x = - 9 and  1

To graph the function we need some more points to accurate graph.

y

y = x2  + 8x - 9

(x, y)

 -1

y=(-1)2+8(-1)-9

 (-1,-16)  

-6

y=(-6)2+8(-6)-9

(-6,-21)

1

y=(1)2+8(1)-9

(1,0)

3

y = (3)2+8(3)-9

(3,24)

Graph

Draw a coordinate plane.

Plot the vertex and axis of symmetry.

Plot the x intercepts, points found in the table.

Connect the points with smooth curve.

Vertex of parabola is (x, y) = (- 4, - 25).

x coordinate is -4 y coordinate is - 25

x intercept is -9 and x intercept is 1.

answered Oct 8, 2014 by david Expert

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