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A student thinks that y= 2x^2 - 12x + 15 is equivalent to y= 2( x-3)^2 + 3. prove algebraically that they are not equivalent.

asked Oct 22, 2014 in CALCULUS by anonymous

1 Answer

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First equation : y1 = 2x2 - 12x + 15

Second equation : y2 = 2(x-3)2 + 3

Apply formula : (a-b)2=a2-2ab+b2

y2 = 2( x2 - 2(x)(3) - 32 ) + 3

y2 = 2( x2 - 6x - 9 ) + 3

y2 = 2x2 - 12x - 18 + 3

y2 = 2x2 - 12x - 15

y2 is not equals to y1

Solution :

First equation (y1 = 2x2 - 12x + 15) and Second equation (y2 = 2(x-3)2 + 3) algebraically that they are not equivalent

 

answered Oct 22, 2014 by lilly Expert

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