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Find (gof)(4) when

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f(x) = 3x−12 g(x) = 2x^2+7x−11?

asked Oct 22, 2014 in ALGEBRA 2 by anonymous

1 Answer

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Step 1 :

Given functions

f(x) = 3x − 12

g(x) = 2x2 + 7x − 11

gof(x) = g [ f(x) ]

g [ 3x − 12 ]

2( 3x − 12 )2 + 7 ( 3x − 12 ) − 11

Apply formula : (a-b)2=a2-2ab+b2

2[ (3x)2 - 2(3x)(12) + (12)2 ] +  21x − 84 − 11

2[ 9x2 - 72x + 144 ] +  21x − 84 − 11

18x2 - 144x + 288 +  21x − 84 − 11

18x2 - 123x + 193

So (gof)(x) = 18x2 - 123x + 193

Step 2 :

(gof)(x) = 18x2 - 123x + 193

Substitute x = 4

(gof)(4) = 18(4)2 - 123(4) + 193

(gof)(4) = -11

Solution :

The solutio is (gof)(4) = -11

answered Oct 22, 2014 by lilly Expert
edited Oct 22, 2014 by lilly

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