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Trigonometry A level question.?

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Trigonometry A level question.?

asked Oct 22, 2014 in TRIGONOMETRY by anonymous

2 Answers

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(i)

The given expression is 3cos x + 4sin x.

To Express this in terms of image.

First we simplify image.

image

image

Now consider  image and then a² + b²

image

Therefore

image

To find the value of α,

image

Now to express a cosx + b sin x in terms of image then image and image.

The Equation is 3cos x + 4sin x where a=3 and b=4.

image

image

Therefore the equation 3cos x + 4sin x is expressed as image.

answered Oct 22, 2014 by dozey Mentor
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(ii)

The given equation is 3cosx + 4sinx = 4.5.

First we write 3cosx + 4sinx = 5 cos(x - 53.13)   (From (i) )

Rewrite the equation as 5 cos(x - 53.13) = 4.5

cos(x - 53.13) = 0.9

image

x - 53.13 = 2nπ ±25.84

for n=0

x - 53.13 = 25.84

x = 79°

Therefore x = 79°.

answered Oct 22, 2014 by dozey Mentor
edited Oct 23, 2014 by bradely

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