Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,726 users

Please help me!

0 votes
Solve each quadratic equation by completing the square and express your answer(s) as EXACT VALUES.

a) x^2 + 6x - 4 = 0

b) 3x^2 - 24x = 17
asked Oct 29, 2014 in PRECALCULUS by anonymous

2 Answers

0 votes

Completing square method

a) The equation x2 + 6x - 4 = 0

Separate variables and constants aside by adding 4 to each side.

x2 + 6x - 4 + 4= 0 + 4

x2 + 6x = 4

To change the expression into a perfect square trinomial add (half the x coefficient)² to each side of the equation.

 Here x coefficient = 6. so, (half the x coefficient)² = (6/2)2= 9

Add 9 to each side

x2 + 6x + 9 = 4 + 9

(x + 3)2= 13

Take square root both sides.

x + 3 = ± √13

Solution x = - 3 + √13 and x = - 3 - √13.

answered Oct 29, 2014 by david Expert
0 votes

Completing square method

b) The equation 3x2 - 24x = 17

Here x2 coefficient is 3 , for perfect square make x2 coefficient 1 by dividing each side by 3.

(3x2 - 24x)/3 = 17/3

x2 - 8x = 17/3

To change the expression into a perfect square trinomial add (half the x coefficient)² to each side of the equation.

 Here x coefficient = -8. so, (half the x coefficient)² = (-8/2)2= 16

Add 16 to each side

x2 - 8x + 16 = 17/3 + 16

(x - 4)2 = ( 17 + 48)/3

(x - 4)2 = 65/3

Take square root both sides.

x - 4 = ± √(65/3)

Solution x = 4 + √(65/3) and x = 4 - √(65/3).

answered Oct 29, 2014 by david Expert

Related questions

asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Nov 6, 2014 in PRECALCULUS by anonymous
asked Nov 5, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 29, 2014 in PRECALCULUS by anonymous
asked Oct 22, 2014 in CALCULUS by anonymous
...