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Solve each quadratic equation by completing the square and express your answer(s) as EXACT VALUES.

a) x^2 + 6x - 4 = 0

b) 3x^2 - 24x = 17
asked Oct 29, 2014 in PRECALCULUS by anonymous

2 Answers

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Completing square method

a) The equation x2 + 6x - 4 = 0

Separate variables and constants aside by adding 4 to each side.

x2 + 6x - 4 + 4= 0 + 4

x2 + 6x = 4

To change the expression into a perfect square trinomial add (half the x coefficient)² to each side of the equation.

 Here x coefficient = 6. so, (half the x coefficient)² = (6/2)2= 9

Add 9 to each side

x2 + 6x + 9 = 4 + 9

(x + 3)2= 13

Take square root both sides.

x + 3 = ± √13

Solution x = - 3 + √13 and x = - 3 - √13.

answered Oct 29, 2014 by david Expert
0 votes

Completing square method

b) The equation 3x2 - 24x = 17

Here x2 coefficient is 3 , for perfect square make x2 coefficient 1 by dividing each side by 3.

(3x2 - 24x)/3 = 17/3

x2 - 8x = 17/3

To change the expression into a perfect square trinomial add (half the x coefficient)² to each side of the equation.

 Here x coefficient = -8. so, (half the x coefficient)² = (-8/2)2= 16

Add 16 to each side

x2 - 8x + 16 = 17/3 + 16

(x - 4)2 = ( 17 + 48)/3

(x - 4)2 = 65/3

Take square root both sides.

x - 4 = ± √(65/3)

Solution x = 4 + √(65/3) and x = 4 - √(65/3).

answered Oct 29, 2014 by david Expert

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