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Find the degree 3 Taylor polynomial approximation to the function

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f(x)=4ln(sec(x)) about x=0.?

asked Nov 1, 2014 in CALCULUS by anonymous

1 Answer

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The function is f(x) = 4ln(sec x)

Taylors Polynomial approximation of degree n for x=a is given as

image

Where n = 3 and x = 0

Then Taylor's Polynomial of approximation

image

Now f(x) = 4ln(sec x)

At x = 0,

f(0) = 4 ln(sec0) = 0

Apply derivative on each side.

image

Now at x = 0

Then f'(0) = 4 tan 0 = 0

Apply derivative on each side.

image

At x = 0,

f''(0) = 4 sec²0

f''(0) = 4

Apply derivative on each side.

image

At x = 0,

f'''(0) = 8 sec²0 tan 0

f'''(0) = 0.

The Taylor's Polynomial of approximation is modified at x=0 as

image

image

Therefore the third degree f(x) = 4ln(sec x) at x=0 using Taylor's Polynomial of approximation is 2x².

answered Nov 1, 2014 by dozey Mentor

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