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Electric circuits?

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ow would you calculate the total resistance in this circuit?

asked Nov 6, 2014 in PHYSICS by anonymous

1 Answer

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From given figure

Resistance values R1 = 10 kΩ , R2 = 10 kΩ , R3 = 22 kΩ , R4 = 33 kΩ

Step 1 :

Resistors R3 = 22 kΩ , R4 = 33 kΩ are in parallel.

Equivalent resistance R5 = R3 // R4

R5 =  (R3R4) / [R3+R4]

R5 =  (22000*33000) / [22000+33000]

R5 =  (726000000) / 55000

R5 =  13200

R5 =  13.2 kΩ

Step 2 :

Resistors R5 = 13.2 kΩ , R2 = 10 kΩ are in seires.

Equivalent resistance R6 = R5 + R2

R6 = 13.2 k + 10 k

R6 = 14.2 kΩ

Step 3 :

Resistors R6 = 14.2 kΩ , R1 = 10 kΩ are in parallel.

Equivalent resistance R7 = R6 // R1

R7 =  (R6R1) / [R6 + R1]

R7 =  (14.2k*10k) / [14.2k+10k]

R7 =  (142*1000000) / 24.2 k

R7 =  5.87 kΩ

Solution :

Total resistance of the circuit is 5.87 kΩ

answered Nov 6, 2014 by lilly Expert

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