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What are the strength and direction of the electric field at the position indicated by the dot in the figure(Figure 1) ?

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Part A) Give your answer in component form. Assume that x

x-axis is horisontal and points to the right, and yy-axis points upward.
Part B) What is the magnitude of the electric field at the position indicated by the dot in the figure.
Part c)What is the angle measured cw from the positive x
x-axis of the electric field at the position indicated by the dot in the figure.
asked Feb 6, 2016 in PHYSICS by anonymous

3 Answers

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Step 1:

(a)

Observe the figure:

The three point charges are , and .

The angle of the field at the dot from the top charge is .

The angle of the field at the dot from the bottom charge is .

The angle of the field at the dot from the top right charge is .

Electric field due to charged particle is , where

image is the permittivity of free space image.

 is the charge of the electron.

 is the distance between the two point charges.

Step 2:

The distance between the top charge and the dot is .

For the charged particle along bottom surface is .

The distance between the bottom charge and the dot is .

For the charged particle along bottom surface is .

The distance between the top left charge and the dot is .

For the charged particle along bottom surface is .

Step 3:

Find the net electric field.

is sum of horizontal and vertical components.

Find the sum of horizontal components.

image

Find the sum of vertical components.

image

Therefore image.

Solution:

image.

answered Feb 6, 2016 by Lucy Mentor
edited Feb 6, 2016 by Lucy
0 votes

(b)

From (a): image.

Find the magnitude of electric field strength.

image

Strength of the electric field is image

answered Feb 6, 2016 by Lucy Mentor
0 votes

(c)

From (a): image.

Find the direction of electric field.

image

Direction of electric field is image clockwise.

answered Feb 6, 2016 by Lucy Mentor

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