Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,734 users

q2 please help by explaining an solving

0 votes

 Calculate the current and power through the 100 Q. resistor in the circuit shown in

asked Mar 5, 2015 in PHYSICS by anonymous

3 Answers

0 votes

Step 1:

Find the current through 100 resistor :

Super Position Theorem :

Take one voltage source at a time and replace all other with short or internal resistance.

Indicate the direction of current in the above circuit.

Equivalent resistance :

100 resistor is in parallel with 40 resistor.

Resistance RT is in series with 60 resistor.

Step 2:

Circuit current :

Current across each resistor :

answered Mar 5, 2015 by yamin_math Mentor
0 votes

Contd....

Step 3:

Now Short circuit the second voltage source.

Indicate the direction of current in the above circuit.

Equivalent resistance :

60 resistor is in parallel with 40 resistor.

Resistance RT is in series with 100 resistor.

Step 4:

Circuit current :

Current across each resistor :

answered Mar 5, 2015 by yamin_math Mentor
0 votes

Contd....

Step 5:

Current through 100 resistor

 = Current produced by 100 resistor due to 80V - Current produced by 100 resistor due to 50V

                   (Since they are in opposite direction)

 = 0.645 - 0.161

 = 0.484

Current through 100 resistor is 0.484 A.

 Step 6:

Power dissipated at 100 :

image

Power dissipated through 100 resistor is 23.4 W.


Solution:

(a) Current through 100 resistor is 0.484 A.

(b) Power dissipated through 100 resistor is 23.4 W.

answered Mar 5, 2015 by yamin_math Mentor

Related questions

asked Mar 12, 2015 in PHYSICS by anonymous
asked Mar 12, 2015 in PHYSICS by anonymous
asked Mar 3, 2015 in PHYSICS by anonymous
asked Mar 12, 2015 in PHYSICS by anonymous
asked Nov 20, 2014 in PHYSICS by anonymous
asked Jul 27, 2014 in PHYSICS by anonymous
asked Jun 29, 2017 in PHYSICS by anonymous
...