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Cot θ +(1/cot θ)

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How would I perform the indicated operation and simplify the result so that there are no quotients?
asked Nov 9, 2014 in TRIGONOMETRY by anonymous

1 Answer

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The expression is cot θ +(1/cot θ)

=(cot θ/1) +(1/cot θ)

= (cot²θ + 1)/cot θ

Recall the formula: cot²θ + 1 = cosec² θ

= (cosec²θ)/cot θ

=(1 / sinθ)²/(cos θ/sinθ)

=1/sinθcos θ

=2/2sinθcos θ

=2/sin2θ

=2cosec 2θ

answered Nov 9, 2014 by bradely Mentor

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