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tanx + cotx = 2 csc 2x

0 votes

Can some one please try to solve?

trigonometric-identities
solving-trigonometric-equations

asked Feb 21, 2014 in TRIGONOMETRY by dkinz Apprentice

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1 Answer

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Left hand side identity = Tanx+Cotx

= Sinx/Cosx + Cosx/Sinx

= (Sin^2x+Cos^2x)/SinxCosx

= 1/SinxCosx

Divide to numarator and denominator by 2.

= 2/2SinxCosx

= 2/Sin2x

= 2 Csc2x

= Right hand side identity.

answered Feb 21, 2014 by friend Mentor

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