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A hyperbola has the equation y^3 + 3yx - x^3 = 9

-->By implicit differentiation w.r.t x, obtain the relation satisfied by dy/dx

-->Compute the coordinates of every point (if any) on the hyperbola at which the
tangent to the hyperbola is parallel to the line y=3x+1
asked Nov 13, 2014 in PRECALCULUS by anonymous

1 Answer

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The curve equation y3 + 3yx - x3 = 9

Differentiate implicitly with respect to x.

3y2(dy/dx) + 3[y + x(dy/dx)] - 3x2 = 0

3y2(dy/dx) + 3y + 3x(dy/dx)] = 3x2

(dy/dx)(3y2 + 3x) = 3x2 - 3y

dy/dx = 3(x2- y)/3(y2 + x)

dy/dx = (x2- y)/(y2 + x)

answered Nov 13, 2014 by david Expert

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