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2cos(2θ) + 1 = 0

asked Nov 18, 2014 in PRECALCULUS by anonymous

1 Answer

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The trigonometric equation 2 cos(2θ) + 1 = 0

2 cos(2θ) = - 1

cos(2θ) = - 1/2

2θ = cos-1(-1/2)

2θ = cos-1(cos 2π/3)

 2θ = 2π/3

θ = π/3

cos(θ) = cos(π/3)

The general solution of cos(x) = cos(α) is x = 2nπ ± α, where n is an integer.

The solutions are θ = 2nπ ± π/3.

answered Nov 18, 2014 by david Expert

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