Trig Equation?

Question

sin^2 B + cos^2 B = 1 + tan^2 B 

Answer 1

The trigonometric equation sin²B + cos²B = 1 + tan²B

{Apply Pythagorean identities sin²x + cos²x = 1}

1 = 1 + tan²B

tan²B = 1 - 1

tan²B = 0

tan²B = tan²(0)

The general solution of tan²(x) = tan²(α) is x = nπ ± α, where n is an integer.

In this case α = 0 , B = x

Solutions are B = nπ.