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Please help me with my trig work?

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tan x-cot x/tan x+cot x
sin x(cot x-csc x)
(cot x+csc x)(1-cosx)

please simplify
asked Apr 5, 2013 in TRIGONOMETRY by angel12 Scholar

3 Answers

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sinx(cotx - cscx)

Recall : Trigonometry formulas cotx =cosx / sinx - 1 / sinx

sinx(cosx / sinx - 1 / sinx)

Recall : ditributive property a(b - c) = ab - ac

sinx(cosx / sinx) - sinx / sinx

cosx - 1.

 

 

answered Apr 5, 2013 by diane Scholar
0 votes

(cotx + cscx)(1 - cosx)

(cosx / sinx + 1 / sinx)(1 - cosx)

(cosx + 1) / sinx(1 - cosx)

(1+ cosx)(1 - cosx) / sinx

Recall :(a - b)( a + b) = a2 - b2

1 -cos2x / sinx

Recall : trigonometry formula

sin2x / sinx

sinx.

answered Apr 5, 2013 by diane Scholar
0 votes

tanx - cotx / tanx + cotx

tanx - cot2x + cotx

Recall :Trigonometry formula tanx = sinx/cosx and cotx = cosx/sinx

(sinx/cosx) - (cos2x/sin2x)  + (cosx/sinx)

Using L.C.M

(sin3x - cos3x + sinx cos2x) / sin2xcosx

Recall : trigonometry formula sin2x + cos2x = 1 then cos2x = 1 -sin2x

[sin3x - cos3x + sinx(1 - sin2x)] / sin2xcosx

[sin3x - cos3x + sinx - sin3x] / sin2xcosx

Recall : Trigonometry formula

(sinx - cos3x) / cosx(1 - cos2x)

(sinx - cos3x) / (cosx - cos3x).

answered Apr 6, 2013 by diane Scholar

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