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Find equation for hyperbola?

0 votes
Center (2,2), Vertex (2,4),
asked May 1, 2013 in PRECALCULUS by mathgirl Apprentice
reopened May 23, 2014 by steve

1 Answer

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The standard form of the equation of a hyperbola with center (h, k) (where a and b are not equals to 0) is (x - h)2/a2 - (y - k)2/b2 = 1 (Transverse axis is Horizontal) or (y - k)2/a2 - (x - h)2/b2 = 1 (Transverse axis is Vertical).

The vertices and foci are, respectively a and c units from the center (h, k) and the relation between a, b and c is b2 = c2 - a2.The center of the hyperbola lies at the midpoint of its vertices or foci.

The center of the hyperbola is (2, 2) and its vertex is (2, 4).

Since the x - coordinate is same in the center and vertex, this is a Vertical hyperbola.

Vertical hyperbola : (y - k)2/a2 - (x - h)2/b2 = 1

Center = (h, k) = (2, 2) ------> (y - 2)2/a2 - (x - 2)2/b2 = 1.

Here find the value of a and b.

Vertices = (h, k ± a) = (2, 4)

k ± a = 4

2 + a = 4 and 2 - a = 4

a = 2 and a = - 2.

The equation of hyperbola is (y - 2)2/4 - (x - 2)2/b2 = 1.

There is no possibility to find the value of b by using given data.

To find the equation of hyperbola, mention the any information for the value of b.

Equation form

(y - k)2/a2 - (x - h)2/b2 = 1

Center

(h, k)

Vertices

(h, k ± a)

Co - vertices

(h ± b, k)

Transverse axis

Vertical

Transverse length

2a

Conjugate axis

Horizontal

Conjugate length

2b

Foci (h, k ± c)
Asymptotes y =  ± a/b (x - h) + k

The equation of hyperbola is (y - 2)2/4 - (x - 2)2/b2 = 1.

answered May 24, 2014 by steve Scholar
edited May 24, 2014 by steve

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