Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,220)
GEOMETRY (864)
ALGEBRA 2 (2,751)
TRIGONOMETRY (1,187)
PRECALCULUS (1,903)
CALCULUS (2,802)
STATISTICS (129)
PHYSICS (659)
CHEMISTRY (137)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration limits substitution-method calculus

13,459 questions

17,854 answers

1,446 comments

808,065 users

F(x) = (4e^x - x^2)(x^3 +1) Calculate the derivative?

0 votes

F(x) = (4e^x - x^2)(x^3 +1) Calculate the derivative?

Using the Product rule
I got to this:
(4e^x - 2x)(x^3 +1) + (4e^x - x^2)(3x^2)

derivatives

asked Feb 14, 2015 in CALCULUS by anonymous

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

Step 1 :

The function is .

Differentiate with respect to x.

Apply product rule of derivatives : .

Consider and .

Solution :

answered Feb 16, 2015 by Thomas Apprentice

Please log in or register to add a comment.

Related questions

F(x) = (4e^x - x^2)(x^3 +1) Calculate the derivative by using the Product rule?

asked Feb 14, 2015 in CALCULUS by anonymous

derivatives
product-rule

Calculate the derivative of f(x)=2x^2+4 by using the defn of the derivative.

asked Feb 14, 2015 in CALCULUS by anonymous

derivatives

Locate all relative extrema using second derivative test: f(x)=4x^3 -27x^2 -30x -4

asked Mar 8, 2014 in CALCULUS by homeworkhelp Mentor

derivative-of-a-function
derivatives

derivative f(x) = sin x + (3/2x^2)

asked Feb 21, 2014 in CALCULUS by abstain12 Apprentice

derivative-of-a-function
derivatives

Locate relative maxima and minima f(x)=-3/4x^4 +1/3x^3 +5x^2 +3

asked Mar 10, 2014 in CALCULUS by rockstar Apprentice

derivative-of-a-function
derivatives

prove that the derivative of y= arccsc(x) is -1/(x(x^2-1)^1/2)

asked Mar 11, 2014 in CALCULUS by johnkelly Apprentice

derivative-of-a-function
derivatives

Find the 3rd derivative of (x+y)^1/2+(x-y)^1/2=9?

asked May 27, 2013 in CALCULUS by linda Scholar

derivatives

Find the derivative of 3^x^2+2^6^x?

asked Mar 5, 2014 in CALCULUS by futai Scholar

derivatives

Find the second derivative, y’’(x) of -3y^2=-2x^3+x-cos(y)

asked Feb 26, 2014 in CALCULUS by angel12 Scholar

derivative-of-a-function
derivatives

using the Chain Rule to find the derivative of F(x).

asked Oct 7, 2018 in CALCULUS by anonymous

derivatives

find the derivative of f(x) =4/x^5+cosx

asked Feb 26, 2014 in CALCULUS by chrisgirl Apprentice

derivative-of-a-function
derivatives

f(x)= (x-2)^54 is divided by x-1

asked Nov 19, 2013 in CALCULUS by linda Scholar

derivatives

Evaluate: f'(3/2) if f(x) = x - lnx?

asked Feb 12, 2015 in CALCULUS by anonymous

derivatives

Find the derivative of the function. f(x) =

asked Sep 15, 2018 in PRECALCULUS by anonymous

derivatives
quotient-rule

find f(x) = x(3x-1)

asked Nov 19, 2013 in CALCULUS by chrisgirl Apprentice

derivatives

f(x) = (sqrt((1-x)/(1+x)))

asked Nov 19, 2013 in CALCULUS by skylar Apprentice

derivatives

Suppose the derivative of a function f is f '(x) = (x + 1)^2 (x - 3)^5 (x - 6)^4.

asked Jan 22, 2015 in CALCULUS by anonymous

increasing-interval
derivative

y = f(x) = 5(x^2-3x +4)^5

asked Nov 21, 2013 in CALCULUS by homeworkhelp Mentor

derivatives
using-chain-rule

Analyze and graph the following function: y = x(9-x^2)^(1/2)

asked Feb 26, 2014 in CALCULUS by abstain12 Apprentice

derivative-of-a-function
derivatives

Find dy/dx for the equation x^3-2x^2y+3xy^2=38

asked Feb 28, 2014 in CALCULUS by andrew Scholar

derivatives
implicit-differntiation

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...