Question

derivative f(x) = sin x + (3/2x^2).

Answer 1

Remember the formulae d/dx(Sinx) = Cosx

d/dx(x^n) = nx^(n-1)

f(x) = Sinx+(3/2x^2)

Apply derivative on each side with respect of x.

f'(x) = d/dx[Sinx+(3/2x^2)]

= d/dx(Sinx)+(3/2)d/dx(x^-2)

f'(x) = Cosx-3/x^3