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write each sum using summation notation.

0 votes

9.2 + 5 + 8 + 11 + ... + 29



10. 6 - 12 + 24 - 48 + ...



11. Find the sum of the arithmetic sequence 2, 4, 6, 8, ..., 70.
 

asked May 30, 2013 in ALGEBRA 2 by payton Apprentice

3 Answers

0 votes

9. The sum of the series 2 + 5 + 8 + 11 +................29

stack sum 3 n minus 1 equal 3 sum n minus sum 1 equal 3 n open parentheses n plus 1 close parentheses divided by 2 minus n with n equal 1 below and 10 on top    (It can rewrite the summation notation)

space space space space space space space space space space space space space space space space space space space space space equal 3 fraction numerator open parentheses 10 close parentheses open parentheses 10 plus 1 close parentheses over denominator 2 end fraction minus 10                (Substitute n = 10)

space space space space space space space space space space space space space space space space space space space space space equal 3 fraction numerator open parentheses 110 close parentheses over denominator 2 end fraction minus 10                            (Simplify)

space space space space space space space space space space space space space space space space space space space space space equal 165 minus 10

space space space space space space space space space space space space space space space space space space space space space equal 155.

 

 

 

 

 

answered May 30, 2013 by diane Scholar
0 votes

10.

6 - 12 + 24 - 48 + ........

The first term a = 6 and common ratio r = -2

s subscript infinity equal end subscript fraction numerator a over denominator 1 minus r end fraction                        (If |r| < 1, The sum of the infinite series formula ) 

s subscript infinity equal end subscript fraction numerator 6 over denominator 1 minus open parentheses minus 2 close parentheses end fraction                 (Substitute a = 6 and r = -2)

s subscript infinity equal end subscript fraction numerator 6 over denominator 1 plus 2 end fraction

s subscript infinity equal end subscript 6 over 3

s subscript infinity equal 2

 

 

 

answered May 30, 2013 by diane Scholar
0 votes

11.

The arithmetic sequence : 2, 4, 6, 8,.........70

The first term of the sequence : a = 2

The common difference            : d = 2

The nth term of sequence         : a + (n - 1)d = 70

                                                           2 + (n - 1)2 = 70

                                                           2n = 70

                                                             n = 35

The sum of the arithmetic sequence : A = n / 2[2a + (n - 1) d 

Substitute a = 2, d = 2 and n = 35

                                                                        = 35 / 2[4 + (35 - 1)2]

                                                                        = 35 / 2[4 + 68]

                                                                        = 35 / 2[72]

                                                                        = 35[36]

                                                                        = 1260.

answered May 31, 2013 by diane Scholar

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