Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,728 users

help-derivatives? shape of?

0 votes

asked May 6, 2015 in CALCULUS by anonymous

3 Answers

0 votes

(5)

Step 1:

The function is .

Differentiate on each side with respect to .

.

Step 2:

Find the critical points.

Since is a polynomial it is continuous at all the point.

Thus, the critical points exist when .

Equate  to zero.

and .

The critical points are and .

Solution :

The critical points are and .

answered May 6, 2015 by Anney Mentor
0 votes

(6)

Step 1:

The function is .

.

The critical points are and .

The test intervals are , and .

The function is increasing on the intervals and .

The function is decreasing on the interval .

Solution :

The function is increasing on the intervals and .

The function is decreasing on the interval .

answered May 6, 2015 by Anney Mentor
edited May 6, 2015 by Anney
0 votes

(7)

Step 1:

The function is .

The critical points are and .

The function is increasing on the intervals and .

The function is decreasing on the interval .

Find the local maximum and local minimum.

The function has a local maximum at , because changes its sign from positive to negative.

Substitute in .

Local maximum is .

The function has a local minimum at , because changes its sign from negative to positive.

Local minimum is .

Solution :

Local maximum is .

Local minimum is .

answered May 6, 2015 by Anney Mentor
reshown May 6, 2015 by casacop

Related questions

asked May 3, 2015 in CALCULUS by anonymous
asked May 3, 2015 in CALCULUS by anonymous
asked Apr 28, 2015 in CALCULUS by anonymous
...