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find the value of f'(pi/4)

0 votes

f(x) =ln(cosx)

calculus
differentiation

asked Oct 18, 2017 in CALCULUS by anonymous
reshown Oct 18, 2017 by bradely

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1 Answer

0 votes

f(x) =ln(cosx)

f'(x) =(1/cosx)(-sinx)

=-tanx

f'(pi/4) =-tan(pi/4)

=-1

answered Oct 19, 2017 by homeworkhelp Mentor

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