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If the graph of y=x^3+ax^2+bx-4 has a point of inflection at (1,6), what is the value of b

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calculus
point
of
point-of-inflection

asked Dec 6, 2019 in CALCULUS by reyesl2 Rookie

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1 Answer

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The derivative: y'= 3x^2 + 2ax + b The second derivative: y"= 6x + 2a =0 -> x= -2a/6 =1 (point of inflection) -> a= -3 Replace a=-3, x=1, y=6 to y=x^3+ax^2+bx-4 -> b=12

answered Jan 30, 2020 by Trage Rookie

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