Find a point on the y-axis that is equidistant from the points (1, –7) and (5, –1)????

Question

a.
(–2, 0)
b.
(0, –2)
c.
(0, 0)
d.
(0, 3)
e.
(0, –4)

Answer 1

Distance formula  :    √(x₂ -x₁)² +(y₂-y₁)²

Given points   (1,– 7) ,   (5,– 1)

b) (0,– 2)

Distance  between  (0,– 2) and (1,– 7)

      Formula  =√(x₂ -x₁)² +(y₂-y₁)²

Substitute (0,– 2) and (1,– 7) in the formula

   √(1 –0)² +(– 7–(– 2))²

  √(1)² +(– 7+2))²

  √(1)² +(– 5))²

  √1+25

   √26

Formula  =√(x₂ -x₁)² +(y₂-y₁)²

Substitute (0,– 2) and (5,– 1) in the formula

        √(5 –0)² +(– 1–(– 2))²

    √(5 )² +(– 1+2)²

     √25 + 1

     √26

Option b is right choice.