Question

Find an equation of the plane that contains all the points that are equidistant from the given points.

(- 3, 1, 2), (6, - 2, 4)

Answer 1

Step 1:

The points are and .

The plane equation passes through normal to the line joining and .

The normal vector to the plane is .

The plane equation is passes through the mid point of and .

The plane equation passes through point and normal is

.

Substitute and in

.

The plane equation is .

Solution:

The plane equation is .