Question

Given the function f(x)=x^2-x+10 find each of the following f(3), f(-8), f(0)

Answer 1

Given Function is f(x)  =  x^2 - x + 10

Substitute x = 3 in f(x)

f(3)  =  (3)^2 - (3) + 10

       =  9 - 3 + 10 

f(3)  =  16.

Substitute x = -8 in f(x)

f(-8)  =  (-8)^2 - (-8) + 10

        =  64 + 8 + 10

f(-8)  =  82

Substitute x = 0 in f(x)

f(0)  =  (0)^2 - (0) + 10

       =  0 - 0 + 10

f(0)  =  10.

Answer :

f(3)  =  16.

f(-8)  =  82

f(0)  =  10.