Question

find the standard form of the equation of the circle whose center and radius are given. (h, k)=(-2,3) r = 4

Answer 1

center, (h, k)=(-2,3) and r =4

Write the relation of circle in stadard form.

(x-h)^2+(y-k)^2 =r^2

(x-(-2))^2+(y-3)^2 =4^2

(x+2)^2+(y-3)^2 =16

Therefore, the stadard form of circle is (x+2)^2+(y-3)^2 =16