Question

A wet bar of soap (mass=103.9 grams) slides without friction down a 2 m long ramp inclined at 9 degrees. How long does it take to reach the bottom? (use g=10.0 m/s^2)

Answer 1

Calculate the force acting on the soap to cause it to slide down, F= mgsinθ

ma =mgsinθ

a =gsinθ=10sin9 =1.564 m/s^2

s =ut +(1/2) at^2

2 = 0+(1/2) (1.564)t^2

t^2 =4/1.564 =2.5575

t =1.6s