Calculus question need help now!!?

Question

solve for x: 2^(x+1)=3^x

Answer 1

Answer:

2^(x+1)= 3^x

We can apply natural log for both sides,

so, ln[2^(x+1)] =ln[ 3^x]

now we can rearrange like this,

(x+1)ln2= x ln 3

(x+1) 0.6931= 1.0986x

0.6931x+0.6931= 1.0986x

(1.0986-0.6931) x= 0.6931

x= 0.6931/ (1.0986-0.6931)

x= 1.7092

Comments

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