Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,106 users

Need help with pre-calculus question?

0 votes

asked May 10, 2014 in CALCULUS by anonymous

1 Answer

0 votes

Given : x = (1/2)t and y = 3t^3 - 1.

Solve x = (1/2)t for t.

t  = 2x.

To eliminate the parameter t, substitute t = 2x in  y = 3t^3 - 1.

y = 3(2x)^3 - 1

y = 3(8x^3) - 1

y = 24x^3 - 1.

answered May 10, 2014 by lilly Expert

Related questions

asked Aug 14, 2014 in PRECALCULUS by anonymous
asked Nov 20, 2014 in PRECALCULUS by anonymous
asked Nov 15, 2014 in PRECALCULUS by anonymous
asked May 1, 2014 in PRECALCULUS by anonymous
...