Welcome :: Homework Help and Answers :: Mathskey.com

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,220)
GEOMETRY (864)
ALGEBRA 2 (2,751)
TRIGONOMETRY (1,187)
PRECALCULUS (1,903)
CALCULUS (2,802)
STATISTICS (129)
PHYSICS (659)
CHEMISTRY (137)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration limits substitution-method calculus

13,459 questions

17,854 answers

1,446 comments

805,772 users

(4x^2 - 9) divide (2x - 3)

0 votes

(4x^2 - 9) divide (2x - 3)

real-numbers

asked Nov 23, 2013 in ALGEBRA 1 by rockstar Apprentice

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

(4x^2-9)

This is in a^2-b^2 form.

here a = 2x, b = 3

We can also write it (2x-3)(2x+3)

There fore (2x-3)(2x+3)/(2x-3)

Cancel the same terms.

= 2x+3

So (4x^2-9)/(2x-3) = 2x+3

answered Nov 23, 2013 by william Mentor

Please log in or register to add a comment.

Related questions

Divide: (2x^3 - x^2 + 3x -1) ÷ (x + 2)

asked Nov 23, 2013 in ALGEBRA 1 by johnkelly Apprentice

real-numbers

divide x³-3x²+4x-2 by x-3

asked Nov 23, 2013 in ALGEBRA 2 by homeworkhelp Mentor

real-numbers
quotient

Divide 5x^3 + 5x^2 +90 by x +3

asked Feb 20, 2014 in ALGEBRA 1 by futai Scholar

dividing-polynomials
real-numbers

Find the real solutions of this equation x^4 + 4x^3 + 2x^2 - x + 6 = 0

asked Nov 23, 2013 in ALGEBRA 2 by angel12 Scholar

real-numbers

how many real solutions of equation x^4 + 4x^3 + 2x^2 - x + 6 = 0

asked Nov 23, 2013 in ALGEBRA 2 by mathgirl Apprentice

real-numbers

divide the first polynomial by the second x³+5x²-8x-12,x-2

asked Nov 23, 2013 in ALGEBRA 1 by mathgirl Apprentice

real-numbers

divide the expression 2x^3-x^2-4x+1/x+2

asked Feb 20, 2014 in ALGEBRA 2 by payton Apprentice

dividing-polynomials

divide 2x^3 +4x^2 -3x -3 by x -1 synthetically

asked Jun 24, 2013 in ALGEBRA 2 by payton Apprentice

synthetic-division

if i divide 2i by x^3-3x^2+4x-12 using synthetic division what is my answer

asked Dec 7, 2013 in ALGEBRA 1 by skylar Apprentice

synthetic-division

use synthetic division to divide 7x^2-4x+12+3x^3 by x+1

asked Dec 7, 2013 in ALGEBRA 1 by linda Scholar

synthetic-division

help me pls

asked Feb 28, 2014 in ALGEBRA 2 by chrisgirl Apprentice

real-numbers

lim as x approaches -1.5 9-4x^2/3+2x=6

asked Dec 15, 2017 in CALCULUS by anonymous

limits

Short Answer: Find the difference (7x^3-6x^2+6) - (2x^2-4x-9)

asked Mar 12, 2014 in ALGEBRA 2 by harvy0496 Apprentice

solving-equations

Compare and contrast the solution of |2x + 3| > 9 and the solution of |4x + 6| > 18.

asked Sep 17, 2015 in ALGEBRA 1 by anonymous

differential-equations

how do you divide (x^4+2x^3-5x^2+3x-1) by (x-1) usin synthetic division

asked Mar 11, 2014 in ALGEBRA 2 by futai Scholar

dividing-polynomials
synthetic-division

how do you divide the polynomial 2x^3-5x^2+3x-1

asked Feb 20, 2014 in ALGEBRA 2 by mathgirl Apprentice

dividing-polynomials
long-division

divide x^3-3x^2+2x-6/x^2+3x-1

asked Feb 20, 2014 in ALGEBRA 2 by abstain12 Apprentice

dividing-polynomials
long-division

find the unknowns usuing either elimination or substitution 2x+6y+3z=9 , 5x-3y-5z=3 , 4x+3y+2z=3

asked Nov 28, 2013 in ALGEBRA 2 by angel12 Scholar

system-of-equations
solving-equations

If the measure of angle one is "2x minus 9" and the measure of angle 2 is "27 minus 4x", solve for x

asked Mar 11, 2014 in GEOMETRY by angel12 Scholar

mesurement-of-the-angles

F(x)=2x+1 and g(x)= x^2-4x+3

asked Jun 25, 2014 in ALGEBRA 1 by anonymous

domain-composite-functions

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...