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in standard (xy) coordinate plane

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in standard (xy) coordinate plane, determine the distance between (2,7) and (1,-4) round to the nearest hundredth

distance-between-points

asked Nov 28, 2013 in GEOMETRY by rockstar Apprentice

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Let the coordinates are (x₁, y₁) = (2, 7) and (x₂, y₂) = (1, - 4)

Distance = √[(x₂ - x₁)² + (y₂ - y₁)² ]

Distance = √[ (1 - 2)² + (- 4 - 7)² ]

= √(1 + 121)

= √122

= 11.045

Distance is 11.05 units.

answered Aug 19, 2014 by david Expert

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