Question

how to solve a(1,4) b(5,5) c(2,2) and d(-5,1) E(-1,0) f(-4,3) using distance formula

Answer 1

Given points are a(1,4),b(5,5),c(2,2),d(-5,1)e(-1,0)f(-4,3)

a(1,4) b(5,5)

Distance between ab = sqrt[(5-1)^2+(5-4)^2]

= Sqrt(16+1) = sqrt(17)

b(5,5) c(2,2)

bc = sqrt[(2-5)^2+(2-5)^2]

bc = sqrt(9+9) = sqrt(18)

c(2,2) d(-5,1)

cd = sqrt[(-5-2)^2+(1-2)^2]

=sqrt[49+1] = sqrt(50)

d(-5,1) e(-1,0)

de = Sqrt[(-1+5)^2+(0-1)^2]

= sqrt[16+1] = sqrt(17)

e(-1,0) f(-4,3)

ef = sqrt[(-4+1)^2+(3-0)^2]

= sqrt[9+9] = sqrt(18)

f(-4,3) a(1,4)

fa = sqrt[(1+4)^2+(4-3)^2]

= sqrt(25+1)

= sqrt (26)

We can observe here the distance between ab and de is equal.

the distance between bc and ef is equal.

Comments

correct answer.