square ABCD has vertices A(-2,-3), B(-4,-1) C(2,5) D(-4,3)

Question

What is the length of a side of the square

Answer 1

A(-2,-3) ,B(-4,1), C(2,5) and D(-4, 3)

Square ABCD has four vertices

The side of the square ABCD = The distance of  AB = √(-4 + 2)² + (-1 + 3)²

                                                                                             = √(-2)² + ( 2)²

                                                                                             = √(4 + 4)

                                                                                             = √(8)

The distance of BC = √(2 + 4)² + (5 + 1)² = √72

Distance of AB not equal to Distance of  BC

Therefore this is not a square.

The problem is wrong.