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How to solve using elemination method state if no solution or infinate

-3x+4y=1

-6x+6y=-3

asked Dec 2, 2013 in ALGEBRA 1 by johnkelly Apprentice

1 Answer

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Elimination method

-3x+4y =1---------> (1)

-6x+6y = -3 ---------> (2)

Multiple to each side of equation (1)by 2.

-6x+8y = 2 -------> (3)

To eliminate the x value, subtract equation (3) from (2).

-6x+6y = -3

-6x+8y = 2

(+) (-)   (-)

__________

-2y = -5

Divide to each side by negitive 2.

-2y/-2 = -5/-2

y = 5/2

Substitute the value of y in (1).

-3x+4*5/2 = 1

-3x+10 = 1

Subtract 10 from each side.

-3x+10-10 = 1-10

-3x = -9

Divide to each side by negitive 3.

-3x/-3 = -9/-3

x = 3

Solution x = 3, y = 5/2.

answered Dec 2, 2013 by william Mentor

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