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Solve each equation by graphing -x^3-3x-2=0

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i need help with this i dont under stand olve each equation by graphing

-x^3-3x-2=0

asked Dec 4, 2013 in ALGEBRA 2 by skylar Apprentice

2 Answers

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The cubic function  y  = - x 3 - 3x - 2

Find the y  - intercept by substituting x  = 0 in the given equation.

y  = - 03 - 3(0) - 2

y  = - 2

The y  - intercept is - 2.

Test points

Make the table of values for the polynomial.

Here i test 4 points to determine whether the graph of polynomials lies above or below the x  axis.

Choose values for x  and find the corresponding values for y .

x

y = - x 3 - 3x - 2 (x, y )

-0.5

y = - (- 0.5)3 - 3(- 0.5) - 2 = - 0.375  (- 0.5, -0.375)

-1

y = - (- 1)3 - 3(- 1) - 2 = 2  (-1, 2)

0.5

y = - ( 0.5)3 - 3( 0.5) - 2 = -3.375 (0.5, -3.375)
1 y = - (1)3 - 3(1) - 2 = -6 (1, -6)

End behavior y  = - x 3 - 3x - 2

Degree of the polynomial is 3 and leading coefficient - 1.

The graph of a polynomial function is always a smooth curve; that is, it has no breaks or corners.

All odd degree polynomials behave on their ends like cubics.

All odd degree polynomials  have ends that head off in opposite directions.depending on whether the polynomial has, respectively, a positive or negative leading coefficient.

The above polynomial odd degree  polynomial with a negative leading coefficient .

So the graph falls to the right and rises to the left.

1.Draw a coordinate plane.

2.Plot the intercept and coordinate points found in the table.

3.Then sketch the graph, connecting the points with a smooth curve.

Graph :

The points where it crosses the x  axis  will give solutions to the polynomial function .

The graph crosses the x  - axis at a point that would suggest a factor.

It crosses the x  - axis at one point hence there are one real root.

x  = - 0.59

 

answered Aug 23, 2014 by david Expert
edited Aug 23, 2014 by david
0 votes

Contd...

Use synthetic division to determine if the given value of is a root of the polynomial.

image

Since f (-0.59) = 0, x = -0.59 is a zero.

The depressed polynomial is image

Since the depressed polynomial of this zero, image, is quadratic,

Use the Quadratic Formula to find the roots of the related quadratic equation

 

image

Roots are

image

image

image

image

image

The function has one real solution at = - 0.59 and two imaginary solutions are at image

answered Aug 23, 2014 by david Expert
edited Aug 23, 2014 by david

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